A.GLS lamps
B.dry cells
C.cinema projectors
D.electric arc furnace
Explanation: The correct answer is GLS lamps.
Submitted by: Academy of Pakistan
Electrical Engineering MCQs: 3,658 practice questions with answer choices and available explanations. Page 168 of 244.
Electrical Engineering MCQs by topic
Basic Electrical MCQs121Power Electronics217Transformers132Transmission and Distribution90D.C. Motors130D.C. Generators120Polyphase Induction Motors99Single Phase Induction Motors110Synchronous Motors122Network Theorems47Economics of Power Generation98A.C. Fundamentals, Circuits and Circuit Theory109Cables57Electrolysis and Storage of Batteries119Electrostatics180Magnetic Circuit28Rectifiers and Converters58Magnetism and Electromagnetism85Electromagnetic Induction85Switchgear and Protection102OP-AMP Circuits24Heating and Welding50Earthing or Grounding11Parallel Circuits25Oscillators28Amplifiers with Negative Feedback18Transistors42Semiconductor Diode44Analog Electronics46Hybrid Parameters12Modulation and Demodulation40Control Systems100Digital Electronics36Electric Traction74Electrical Engineering Materials100Electrical Machine Design103Electronic Instruments30Field Effect Transistors - FET47Industrial Drives70Integrated Circuits15Measurement and Instrumentation109Multi-Stage Transistor Amplifiers40Power Generation121Regulated D.C. Power Supply39SCR (Silicon Controlled Rectifiers)25Semiconductor Theory35Single Stage Transistor Amplifiers38Solid-State Switching Circuits29Transistor Audio Power Amplifiers39Transistor Biasing40Transistor Tuned Amplifiers40Series-Parallel Circuits29Passive Filters20Operational Amplifier30
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Electrical Engineering MCQs
Showing page 168 of 244 · 3,658 total solved questions available.
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A.Vdc = 2Vm/π, PIV=2vm
B.Vdc = Vm/π, PIV=Vm
C.Vdc = Vm/π, PIV=2Vm
D.Vdc = 2Vm/π, PIV=Vm
Explanation: The correct answer is Vdc = 2Vm/π, PIV=2vm.
Submitted by: Academy of Pakistan
A.Average value of current and voltage to its root mean square value
B.Peak value of current and voltage to its root mean square value
C.Root mean square value of voltage and current to its average value
D.Root mean square value of voltage and current to its peak value
Explanation: The correct answer is Root mean square value of voltage and current to its average value.
Submitted by: Academy of Pakistan
A.maximum
B.nil
C.minimum
D.none of the above
Explanation: The correct answer is maximum.
Submitted by: Academy of Pakistan
A.Both (A) and (B)
B.They are mechanically strong
C.They do not require any voltage for filament heating
D.None of the above
Explanation: The correct answer is Both (A) and (B).
Submitted by: Academy of Pakistan
A.low resistance as well as low inductiance
B.high resistance and low inductance
C.low resistance and high inductance
D.high resistance as well as high inductance
Explanation: The correct answer is low resistance and high inductance.
Submitted by: Academy of Pakistan
A.Pb
B.Pb02
C.PbO
D.PbSC-4
Explanation: The correct answer is PbSC-4.
Submitted by: Academy of Pakistan
A.The same as
B.More than
C.Less than
D.None of the above
Explanation: The correct answer is More than.
Submitted by: Academy of Pakistan
A.all above methods
B.resistance rise method
C.thermometer method
D.embedded temperature method
Explanation: The correct answer is all above methods.
Submitted by: Academy of Pakistan
A.5.5 m
B.10.5 m
C.7.0 m
D.4.3 m
Explanation: The correct answer is 7.0 m.
Submitted by: Academy of Pakistan
A.reaction steam turbine
B.velocity compounded impulse steam turbine
C.pressure velocity compounded steam turbine
D.pressure compounded impulse steam turbine
Explanation: The correct answer is pressure compounded impulse steam turbine.
Submitted by: Academy of Pakistan
A.induced and forced fan
B.induced fan
C.all of the above
D.forced fan
Explanation: The correct answer is all of the above.
Submitted by: Academy of Pakistan
A.Provides high stability
B.Is sensitive to changes in ß
C.Is complicated
D.None of the above
Explanation: The correct answer is Is sensitive to changes in ß.
Submitted by: Academy of Pakistan
A.common source configuration
B.common gate configuration
C.none of the above
D.common drain configuration
Explanation: The correct answer is common gate configuration.
Submitted by: Academy of Pakistan
A.the stator current will be zero
B.the back e.m.f. will be more than the supply voltage
C.none of the above
D.the stator current will be very high
E.the stator current will be very small
Explanation: The correct answer is the stator current will be zero.
Submitted by: Academy of Pakistan