3192Chemical EngineeringMedium
Avogadro’s number is equal to________?
A6.023 × 1016 molecules/kg.mole
B6.023 × 1026 molecules/gm.mole
C6.023 × 1023 molecules/gm.mole
D6.023 × 1023 molecules/kg.mole
Correct answer
C. 6.023 × 1023 molecules/gm.mole
Explanation
The correct answer is 6.023 × 1023 molecules/gm.mole.