Colebrook equation for friction factor in turbulent ... - Solved MCQs & Answer

4748Chemical EngineeringMedium

Colebrook equation for friction factor in turbulent flow is given by, f-0.5 = -4 loge [(ε/D) + (1.26/NRe √F). It reduces to Nikuradse equation for a value of (ε/D) equal to ________?

A0.5

Correct answer

B. 1

Explanation

The correct answer is 1.

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