An elevator weighing 3.5 x 10-6 N is raised to a height of 1000 m in the absence of friction, the work done is_________________?
A3.5 x 10-3 J
B3.5 x 106 J
C3.5 x 104 J
D3.5 x 109 J
Correct answer
A. 3.5 x 10-3 J
Explanation
To find the work done in raising the elevator, we can use the formula for work done against gravity: Work=Force×Distance Given: Force (FFF) = 3.5×10−63.5 \times 10^{-6}3.5×10−6 N Distance (ddd) = 1000 m Substituting the given values: Work=3.5×10−6N×1000m Work=3.5×10−3J If correct, the work done is 3.5×10−33.5 \times 10^{-3}3.5×10−3 Joules.