A stone is thrown upward from the top of a 59.4m high cliff with an upward velocity component of 19.6m/s how long is the stone in the air?
A6.00 s
B7.00 s
C4.00 s
D5.00 s
Correct answer
A. 6.00 s
Explanation
Applying newtons formula, S= ut + (1/2)at^2 Let downwards direction be (-) be , so -59.4 = 19.5t – (1/2) 10t^2 By Sloving this you will get ,t= 6 sec