A body is falling freely under gravity. How much distance it falls during an interval of time between 1st and 2nd seconds of its motion, taking g=10 ?
Correct answer
C. 15 m
Explanation
answer is 15 m S=ut+1/2gt^2 u=0 ,g = 10ms-2 During ist time interval S1=0+1/2(10)(1)^2 S1=5m During 2nd time interval S2=0+1/2(10)(2)^2 S2=20m Distance covered by body during an interval of time between first and second seconds of its motion = (S2 – S1 ) = 20–5 = 15m .